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Problem 297: Zeckendorf Representation
(see projecteuler.net/problem=297)
Each new term in the Fibonacci sequence is generated by adding the previous two terms.
Starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89.
Every positive integer can be uniquely written as a sum of nonconsecutive terms of the Fibonacci sequence.
For example, 100 = 3 + 8 + 89.
Such a sum is called the Zeckendorf representation of the number.
For any integer n>0, let z(n) be the number of terms in the Zeckendorf representation of n.
Thus, z(5) = 1, z(14) = 2, z(100) = 3 etc.
Also, for 0 < n < 10^6, sum{z(n)} = 7894453.
Find sum{z(n)} for 0 < n < 10^17.
My Algorithm
Often I write a simple brute-force program which produces the correct result for small inputs.
The function zeckendorf
returns the number of terms in the Zeckendorf representation of a single number.
According to the Wikipedia page on the Zeckendorf theorem (en.wikipedia.org/wiki/Zeckendorf's_theorem) a greedy repeated search
for the largest Fibonacci numbers <= the current number is sufficient.
Then I printed the first 100 numbers (and their sum) and discovered the pattern:
the number of terms repeats after each new Fibonacci number, abeit increased by one. For example:
numberzeckendorf(number)
sumfiboSum
1111
2122
3133
425
5166
628
7210
811111
9213
10215
11217
12320
1312121
14223
15225
16227
17330
18232
19335
20338
2113939
The Zeckendorf representation is always 1 for a Fibonacci number (which are bold in the table above).
My array fiboSum
contains the running total (the sum) for each n-th Fibonacci number:
fiboSum[n] = fiboSum[n - 1] + fiboSum[n - 2] + fibonacci[n - 2] - 1
Using that relationship my function search
recursively subtracts the largest possible Fibonacci number
while adding the relevant value fiboSum
.
Note
The zeckendorf
function isn't needed anymore but I didn't remove it because my gut tells me I could use it in the future ...
Interactive test
You can submit your own input to my program and it will be instantly processed at my server:
This is equivalent toecho 1000000 | ./297
Output:
Note: the original problem's input 100000000000000000
cannot be entered
because just copying results is a soft skill reserved for idiots.
(this interactive test is still under development, computations will be aborted after one second)
My code
… was written in C++11 and can be compiled with G++, Clang++, Visual C++. You can download it, too. Or just jump to my GitHub repository.
#include <iostream>
#include <vector>
// all Fibonacci numbers below 10^17
std::vector<unsigned long long> fibonacci;
// and the sum according to my algorithm description
std::vector<unsigned long long> fiboSum; // fibonacci.size() == fiboSum.size()
// see en.wikipedia.org/wiki/Zeckendorf's_theorem
// return the length of the Zeckendorf representation of x
unsigned int zeckendorf(unsigned long long x)
{
unsigned int result = 0;
// greedy search:
// in each step subtract the largest possible Fibonacci number
unsigned int pos = fibonacci.size() - 1;
while (x > 0)
{
while (fibonacci[pos] > x)
pos--;
x -= fibonacci[pos];
result++;
}
return result;
}
// compute sum of the length of all Zeckendorf representations from 1 to x
unsigned long long search(unsigned long long x)
{
// find largest Fibonacci number <= x
auto pos = 0;
while (fibonacci[pos + 1] <= x)
pos++;
// strip off that Fibonacci number
auto reduced = x - fibonacci[pos];
// done ?
if (reduced == 0)
return fiboSum[pos];
// still more 1s in the binary Zeckendorf representation left ...
return fiboSum[pos] + reduced + search(reduced);
}
int main()
{
unsigned long long limit = 100000000000000000ULL;
std::cin >> limit;
// note: it took me a while to figure out that because of F(1) = F(2) = 1
// I am not allowed to represent 3 as F(1) + F(3) (which is 3 = 1 + 2)
// even though F(1) and F(3) are not consecutive
// if I remove F(1) (or F(2)) then that ambiguity disappears and everything's fine
// start with Fibonacci numbers F(2) and F(3)
fibonacci = { 1, 2 };
// F(2) has length 1, F(3) as length 1 as well plus 1 from F(2)
fiboSum = { 1, 1+1 };
// find all Fibonacci number below 10^17
while (fibonacci.back() < limit)
{
auto size = fibonacci.size();
auto nextFibo = fibonacci[size - 1] + fibonacci[size - 2];
fibonacci.push_back(nextFibo);
// "special" sum of Fibonacci numbers
auto nextSum = fiboSum [size - 1] + fiboSum [size - 2] + fibonacci[size - 2] - 1;
fiboSum.push_back(nextSum);
}
// NOT including 10^17
limit--;
// display result
std::cout << search(limit) << std::endl;
// my old test code for the first 100 numbers
//auto sum = 0;
//for (auto i = 1; i < 100; i++)
//{
// auto current = zeckendorf(i);
// sum += current;
// std::cout << i << "=" << current << " " << sum << " / " << search(i) << std::endl;
//}
return 0;
}
This solution contains 18 empty lines, 29 comments and 2 preprocessor commands.
Benchmark
The correct solution to the original Project Euler problem was found in less than 0.01 seconds on an Intel® Core™ i7-2600K CPU @ 3.40GHz.
(compiled for x86_64 / Linux, GCC flags: -O3 -march=native -fno-exceptions -fno-rtti -std=gnu++11 -DORIGINAL
)
See here for a comparison of all solutions.
Note: interactive tests run on a weaker (=slower) computer. Some interactive tests are compiled without -DORIGINAL
.
Changelog
July 25, 2017 submitted solution
July 25, 2017 added comments
Difficulty
Project Euler ranks this problem at 35% (out of 100%).
Links
projecteuler.net/thread=297 - the best forum on the subject (note: you have to submit the correct solution first)
Code in various languages:
Python github.com/LaurentMazare/ProjectEuler/blob/master/e297.py (written by Laurent Mazare)
Python github.com/Meng-Gen/ProjectEuler/blob/master/297.py (written by Meng-Gen Tsai)
Python github.com/shlomif/project-euler/blob/master/project-euler/297/euler_297.py (written by Shlomi Fish)
Python github.com/smacke/project-euler/blob/master/python/297.py (written by Stephen Macke)
Python github.com/steve98654/ProjectEuler/blob/master/297.py
C++ github.com/roosephu/project-euler/blob/master/297.cpp (written by Yuping Luo)
Java github.com/thrap/project-euler/blob/master/src/Java/Problem297.java (written by Magnus Solheim Thrap)
Go github.com/frrad/project-euler/blob/master/golang/Problem297.go (written by Frederick Robinson)
Those links are just an unordered selection of source code I found with a semi-automatic search script on Google/Bing/GitHub/whatever.
You will probably stumble upon better solutions when searching on your own.
Maybe not all linked resources produce the correct result and/or exceed time/memory limits.
Heatmap
Please click on a problem's number to open my solution to that problem:
green | solutions solve the original Project Euler problem and have a perfect score of 100% at Hackerrank, too | |
yellow | solutions score less than 100% at Hackerrank (but still solve the original problem easily) | |
gray | problems are already solved but I haven't published my solution yet | |
blue | solutions are relevant for Project Euler only: there wasn't a Hackerrank version of it (at the time I solved it) or it differed too much | |
orange | problems are solved but exceed the time limit of one minute or the memory limit of 256 MByte | |
red | problems are not solved yet but I wrote a simulation to approximate the result or verified at least the given example - usually I sketched a few ideas, too | |
black | problems are solved but access to the solution is blocked for a few days until the next problem is published | |
[new] | the flashing problem is the one I solved most recently |
I stopped working on Project Euler problems around the time they released 617.
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I scored 13526 points (out of 15700 possible points, top rank was 17 out of ≈60000 in August 2017) at Hackerrank's Project Euler+.
My username at Project Euler is stephanbrumme while it's stbrumme at Hackerrank.
Look at my progress and performance pages to get more details.
Copyright
I hope you enjoy my code and learn something - or give me feedback how I can improve my solutions.
All of my solutions can be used for any purpose and I am in no way liable for any damages caused.
You can even remove my name and claim it's yours. But then you shall burn in hell.
The problems and most of the problems' images were created by Project Euler.
Thanks for all their endless effort !!!
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