<< problem 493 - Under The Rainbow | Eight Divisors - problem 501 >> |
Problem 500: Iterative Circle Packing
(see projecteuler.net/problem=500)
The number of divisors of 120 is 16.
In fact 120 is the smallest number having 16 divisors.
Find the smallest number with 2^500500 divisors.
Give your answer modulo 500500507.
My Algorithm
The number of divisors depends on the exponents of its prime factors (see en.wikipedia.org/wiki/Divisor_function).
numDivisors = (exponent1 + 1) * (exponent2 + 1) * ... * (exponentN + 1)
e.g. 120 = 2^3 * 3^1 * 5^1 therefore (3+1)(1+1)(1+1) = 4 * 2 * 2 = 16 divisors
Every number with exactly 16 divisors has the form
(A) prime_1^15 or
(B) prime_1^7 * prime_2^1 or
(C) prime_1^3 * prime_2^3 or
(D) prime_1^3 * prime_2^1 * prime_3^1 or
(E) prime_1^1 * prime_2^1 * prime_3^1 * prime_4^1
The most primes are needed when all exponents are 1 (case E): (1 + 1)(1+1)...(1+1) = (1+1)^n = 2^n
Since 16 = 2^4 I need at most 4 primes to find the smallest number with 16 divisors.
In general, the smallest such number is produced when the primes are minimized and their exponents "optimized":
- choose the first n primes (maybe I don't need all of them, but computing all of them is always safe)
- if prime_2 > prime_1 then exponent_2 <= exponent_1 because otherwise I could swap the exponents and get a smaller number
divisors smallest number
2= 2^12= 2^1
4= 2^26= 2^1 * 3^1
8= 2^324= 2^3 * 3^1
16= 2^4120= 2^3 * 3^1 * 5^1
If I have the proper exponents for the smallest number with 2^n exponents then there are two ways to get the smallest number with 2^{n+1} exponents:
- include a new prime with exponent 1 => adds a (1 + 1) term, thus multiplying the number of divisors by 2
- increment the exponent of an existing prime by exponent_N + 1 => converting (exponent_N + 1) to (exponent_N + 1 + exponent_N + 1) = 2(exponent_N + 1)
The trick is to decide whether to go with the first or the second case. And if the second case is chosen, then which prime to adjust:
I keep a priority queue
candidates
and always pick the smallest prime^exponent.A simple struct called
Term
represents such a term, can be sorted and can "double" itself to get the next term.
Interactive test
You can submit your own input to my program and it will be instantly processed at my server:
This is equivalent toecho 4 | ./500
Output:
Note: the original problem's input 500500
cannot be entered
because just copying results is a soft skill reserved for idiots.
(this interactive test is still under development, computations will be aborted after one second)
My code
… was written in C++11 and can be compiled with G++, Clang++, Visual C++. You can download it, too. Or just jump to my GitHub repository.
#include <iostream>
#include <unordered_map>
#include <queue>
#include <vector>
// ---------- standard prime sieve from my toolbox ----------
// odd prime numbers are marked as "true" in a bitvector
std::vector<bool> sieve;
// return true, if x is a prime number
bool isPrime(unsigned int x)
{
// handle even numbers
if ((x & 1) == 0)
return x == 2;
// lookup for odd numbers
return sieve[x >> 1];
}
// find all prime numbers from 2 to size
void fillSieve(unsigned int size)
{
// store only odd numbers
const unsigned int half = (size >> 1) + 1;
// allocate memory
sieve.resize(half, true);
// 1 is not a prime number
sieve[0] = false;
// process all relevant prime factors
for (unsigned int i = 1; 2*i*i < half; i++)
// do we have a prime factor ?
if (sieve[i])
{
// mark all its multiples as false
unsigned int current = 3*i+1;
while (current < half)
{
sieve[current] = false;
current += 2*i+1;
}
}
}
// ---------- problem specific code ----------
struct Term
{
unsigned int prime;
unsigned int exponent;
unsigned long long value; // = pow(prime, exponent)
// prime^exponent = value
Term(unsigned int prime_, unsigned int exponent_, unsigned long long value_)
: prime(prime_), exponent(exponent_), value(value_)
{}
// return a new Term with incremented exponent
Term next() const
{
return Term(prime, 2 * exponent, value * value);
}
// deliberately ">" instead of "<" to convert max-heap to min-heap
bool operator<(const Term& other) const
{
return value > other.value;
}
};
unsigned int solve(unsigned int value, unsigned int modulo)
{
// primes and their exponents to be considered next when computing the number
std::priority_queue<Term> candidates;
// fill with all primes^1
unsigned int currentPrime = 1;
while (candidates.size() < value)
{
++currentPrime;
while (!isPrime(currentPrime))
currentPrime++;
// prime^1 = prime
candidates.emplace(Term(currentPrime, 1, currentPrime));
}
// primes and their exponents actually used for the number
// [prime] => [prime^exponent] % modulo
std::unordered_map<unsigned int, unsigned long long> choice;
// iterate over all exponents
for (unsigned int i = 0; i < value; i++)
{
// fetch smallest prime^exponent
auto current = candidates.top();
// store "new" prime or adjust existing
if (choice.count(current.prime) == 0)
{
choice[current.prime] = current.value;
}
else
{
choice[current.prime] *= current.value;
choice[current.prime] %= modulo;
}
// update queue
candidates.pop();
candidates.push(current.next());
}
// multiply all values of used primes
unsigned long long result = 1;
for (auto x : choice)
result = (result * x.second) % modulo;
return result;
}
int main()
{
// I need all primes up to 7370029 (determined by running the program multiple times)
fillSieve(7400000);
unsigned int exponent = 500500;
std::cin >> exponent;
std::cout << solve(exponent, 500500507) << std::endl;
return 0;
}
This solution contains 23 empty lines, 27 comments and 4 preprocessor commands.
Benchmark
The correct solution to the original Project Euler problem was found in 0.22 seconds on an Intel® Core™ i7-2600K CPU @ 3.40GHz.
Peak memory usage was about 30 MByte.
(compiled for x86_64 / Linux, GCC flags: -O3 -march=native -fno-exceptions -fno-rtti -std=gnu++11 -DORIGINAL
)
See here for a comparison of all solutions.
Note: interactive tests run on a weaker (=slower) computer. Some interactive tests are compiled without -DORIGINAL
.
Changelog
September 11, 2017 submitted solution
September 11, 2017 added comments
Difficulty
Project Euler ranks this problem at 15% (out of 100%).
Links
projecteuler.net/thread=500 - the best forum on the subject (note: you have to submit the correct solution first)
Code in various languages:
Python github.com/evilmucedin/project-euler/blob/master/euler500/500.py (written by Den Raskovalov)
Python github.com/Meng-Gen/ProjectEuler/blob/master/500.py (written by Meng-Gen Tsai)
Python github.com/nayuki/Project-Euler-solutions/blob/master/python/p500.py (written by Nayuki)
C++ github.com/ngthanhtrung23/ProjectEuler/blob/master/P5XX/501.cpp (written by Trung Nguyen)
C++ github.com/roosephu/project-euler/blob/master/500.cpp (written by Yuping Luo)
Java github.com/nayuki/Project-Euler-solutions/blob/master/java/p500.java (written by Nayuki)
Perl github.com/gustafe/projecteuler/blob/master/500-Problem-500.pl (written by Gustaf Erikson)
Those links are just an unordered selection of source code I found with a semi-automatic search script on Google/Bing/GitHub/whatever.
You will probably stumble upon better solutions when searching on your own.
Maybe not all linked resources produce the correct result and/or exceed time/memory limits.
Heatmap
Please click on a problem's number to open my solution to that problem:
green | solutions solve the original Project Euler problem and have a perfect score of 100% at Hackerrank, too | |
yellow | solutions score less than 100% at Hackerrank (but still solve the original problem easily) | |
gray | problems are already solved but I haven't published my solution yet | |
blue | solutions are relevant for Project Euler only: there wasn't a Hackerrank version of it (at the time I solved it) or it differed too much | |
orange | problems are solved but exceed the time limit of one minute or the memory limit of 256 MByte | |
red | problems are not solved yet but I wrote a simulation to approximate the result or verified at least the given example - usually I sketched a few ideas, too | |
black | problems are solved but access to the solution is blocked for a few days until the next problem is published | |
[new] | the flashing problem is the one I solved most recently |
I stopped working on Project Euler problems around the time they released 617.
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I scored 13526 points (out of 15700 possible points, top rank was 17 out of ≈60000 in August 2017) at Hackerrank's Project Euler+.
My username at Project Euler is stephanbrumme while it's stbrumme at Hackerrank.
Look at my progress and performance pages to get more details.
Copyright
I hope you enjoy my code and learn something - or give me feedback how I can improve my solutions.
All of my solutions can be used for any purpose and I am in no way liable for any damages caused.
You can even remove my name and claim it's yours. But then you shall burn in hell.
The problems and most of the problems' images were created by Project Euler.
Thanks for all their endless effort !!!
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